Answers:
PH = 7.56, that is moderate alkalaemia
HCO3 = 38.4 mmol/L, so we have metabolic alkalosis.
Next, we will calculate the compensation. For metabolic alkalosis we use the following equation:
Category Archives: Advanced EM Cases
Imaging Case of the Week 554 Answer
Imaging Case of the Week 553 Answer
The chest x-ray shows Continue reading
Imaging Case of the Week 552 Answer
The chest x-ray shows bilateral skin folds simulating pneumothoraces. Continue reading
Imaging Case of the Week 554
The following chest x-ray is from an adult with irregular heart beat. What can be seen? Continue reading
Lab case 406
An alcoholic man presented to the emergency department after suffering from a seizure. His venous blood gases showed the following:
PH = 7.56
pCO2 = 42 mmHg
Lab case 405 interepretation
Answers:
PH = 7.30, that is mild acidaemia.
pCO2 = 65 mmHg. So, we have respiratory acidosis.
Next, we need to look at the compensation. Compensation for respiratory acidosis is different between acute and chronic cases.
Imaging Case of the Week 553
The following chest x-rays are from a young adult with chest pain. What can be seen? Continue reading
Imaging Case of the Week 552
The chest x-ray is from a patient with severe dyspnoea. Patient has a past history of chronic airway obstruction. What can be seen? Continue reading
Lab case 405
60 year-year-old man with history of DM and x-smoker but not known to have COPD. Presented to an emergency department with shortness of breath. His blood gases showed the following:
PH = 7.30
pCO2 = 65 mmHg